using a well optimized algorithm

Hello Jerry I think it is possible to transmit at speeds (meaning serial transmission via the tape recorder port) about 1-2 kb per second. That. 48 KB Spectrum The whole thing can be filled, you can calculate how long it will take ;) A specific example: all information is transmitted byte by byte, 10 bits (+2 bits parity), on the transmitter side there are almost no problems with recognition, on On the receiver side, apparently 3-5 measurements need to be taken, i.e. 3-5 teams In A,(#FE) with all the equipment Specifically: IN A,(254) ;+11 cycles ADD A,D ; D=#40, the required bit goes to CY LD A,E ; E=0 ADD A,B ;+12 clock cycles, B stores the counter of identical measurements = 1 LD B,A ; +4 bars total 5*27=135 clock cycles (for 5 times checking the transmission of 1 bit) ;at the end, of course, check the level LD A,B CP 4; 1 failure is allowed, i.e. 4 identical measurements JR NC,BIT1 ; got bit = 1 CP 2 JR C,BIT0 ; got bit = 0 ERROR: END ; about 160 clock cycles per bit, transmission frequency = 20 kHz, divide by 10 = number of bits, it turns out 2 kbytes per second peak capacity if the wire good and the ports are clean ;) do not make noise on themselves ;)) If there is (as I have in the Baltic) a serial port, everything is simpler, of course well... The question remains: has anyone connected 2 Spectrums in this form?

Hello Jerry I think it is possible to transmit at speeds (meaning serial transmission via the tape recorder port) about 1-2 kb per second. That. 48 KB Spectrum The whole thing can be filled, you can calculate how long it will take ;) A specific example: all information is transmitted byte by byte, 10 bits (+2 bits parity), on the transmitter side there are almost no problems with recognition, on On the receiver side, apparently 3-5 measurements need to be taken, i.e. 3-5 teams In A,(#FE) with all the equipment Specifically: IN A,(254) ;+11 cycles ADD A,D ; D=#40, the required bit goes to CY LD A,E ; E=0 ADD A,B ;+12 clock cycles, B stores the counter of identical measurements = 1 LD B,A ; +4 bars total 5*27=135 clock cycles (for 5 times checking the transmission of 1 bit) ;at the end, of course, check the level LD A,B CP 4; 1 failure is allowed, i.e. 4 identical measurements JR NC,BIT1 ; got bit = 1 CP 2 JR C,BIT0 ; got bit = 0 ERROR: END ; about 160 clock cycles per bit, transmission frequency = 20 kHz, divide by 10 = number of bits, it turns out 2 kbytes per second peak capacity if the wire good and the ports are clean ;) do not make noise on themselves ;)) If there is (as I have in the Baltic) a serial port, everything is simpler, of course well... The question remains: has anyone connected 2 Spectrums in this form?

Press RESET immediately, Valery Grigoriev! On Fri, 28 Oct 05 19:34:26 +0400, Grigoriev Valery wrote: GV> I think it can be transmitted at speeds (meaning serial GV> transmission via the tape recorder port) about 1-2 kb per second. That. 48 KB Spectrum GV> can be completely filled, you can calculate how long it will take ;) Zhavoronkov Sergejj -- 115200 delal. Ja ogranichilsja na urovne 38400. GV> ; about 160 clock cycles per bit, transmission frequency = 20 kHz, divide by 10 = GV> number of bits, resulting in 2 kbytes per second peak capacity if GV> the wire is good and the ports are clean ;) they don’t make noise on themselves ;)) :-O GV> If you have (as I have in the Baltic) a serial port, everything is simpler GV> of course... The question remains: has anyone connected 2 in this form GW> Spectrum? Spectrum and PC via COM-port.