RGB

Hello. DO> th topic: We throw one screen like this LD SP,.... DO> LD HL,DATA SCREEN DO> PUSH HL DO> LD HL,DATA SCREEN2 DO> PUSH HL Well, this is the fastest throwing method DO> and so this thing takes us about 4240 cycles, let’s sum it up DO> 64512+4240=68752 well, since we have the slowest car DO> this is basically a scorpion, and it has about 69000 clock cycles (my KAYA DO> about the same), in short, judge for yourself, maybe I didn’t understand something DO>, or maybe (I had one thought) in that viewer there is a switch of screens DO> is done according to a different principle. Let's start counting. If you do this, then the screen will be drawn, when the beam passes along the curb, and therefore everything will be cut somewhere in the second half of the screen. Now my method: 1. Place 1 picture on the second screen 2. We place the remaining two, in the form of the procedures written above, and perhaps it is possible simpler. 3. Work: 3.1. turn on screen 2, and fill in the next picture on the screen, I did construction along familiar lines (8 graphic lines, 1 attributes), i.e. ld bc ATTR ld sp,Line0 ld hl, data push hl ... ld sp,Line7 ld hl, data push hl ... ld sp,Line0Attrpush bc ... in this way I finished building 2 pictures in 1.2 interruptions (well, music was still playing, the keys were being processed, etc.). 3.2 took a short break and began to build picture 3, ending with the display 1 from the second screen. As a result, it turned out that out of 3 interruptions I used 2.6 and the rest of the time didn't do anything :-) Now step by step again: 1. Show 1 picture (2nd screen), draw 2nd picture on the main screen. 2. Show 2nd picture (1 screen), finish drawing 2nd picture, start drawing 3, but you need to start after the beam has passed, so that there are no glitches. 3. Show the 3rd picture (1 screen), complete the 3rd picture, then wait for the frame and all over again. That's all. /Sergey/ [] With a large carriage of regards and vicious people. (Pickup from SVERDLOVSK-SORTING station wagon #659839002)