Subject: Assembler for coffee.
Author: Rezonal / Ufo group
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This article will discuss:
1. Answers to questions from Sergei Parfenov
St. Petersburg.
a) run out of tunes compiled
under their programs;
b) on the ACME loaders;
c) using the screen file Art
Studio;
d) the solution of certain problems.
2. Maximum speed of
conclusion of sprites.
3. Theoretically, the fastest ACT
proper output point.
4. Using the stack as the most rapid
rogo way to copy from one
area to another.
Running compiled tunes.
I do not know what the problem would have occurred to the
Sergei, so as accurately describe
precisely those actions which must perform in order to use
Mouzon of program. Unfortunately, I found PT
version 2.0, I use PT 2.1.
1) After downloading the PT, select compile.
2) On the issue include player-hole. <Yes>.
3) Suppose, for example, choose the address
50000.
4) Appears plaque:
INIT: 50,000
PLAY: 50006
DELAY: 52607
LEN: 6561
5) recorded the first two numbers.
6) In Basic'e testing:
a) load the compiled file;
b) write in (nerve please click
41st key) Basic'e:
10 RAND USR 15619: REM: LOAD "..." CO
DE
20 RAND USR pervoe_chislo (50000)
30 RAND USR vtoroe_chislo (50006)
40 GOTO 30
That's for sure. If Mouzon played, the more Apply the TASM.
And write:
ORG 25000; For example
CALL pervoe_chislo (50000)
loop CALL vtoroe_chislo (50006)
LD A, # 7F
IN A, (254)
RRCA
JR C, loop; If SPACE is not pressed
JP pervoe_chislo (stop Mouzon)
Just before you start be sure to get yourself Mouzon ;-).
Hopefully it will work.
Spouts at ACME.
First, it's simple:
1) Run TASM;
2) We leave in BASIC, and write the first row
Coy:
1 REM ******************************
Characters "*" need to put as much
how many bytes are in your boot.
For a start - a little more (say 64 bytes)
3) Go back to the TASM
4) and write:
ORG 23872
db 1,5
db kolichestvo_sektorov_fayla
; C = 5
; B = dlina_fayla_v_sektorah
LD DE, (23796)
LD HL, adres_zagruzki_fayla
CALL 15635
JP adres_zapuska_fayla
5) Compile, go to BASIC
6) We write in BASIC:
2 CLEAR stack: RAND USR 23872
7) Take a blank disk and insert at the disco
waters.
8) SAVE "ProgramName" LINE 1
9) Click RESET.
10) Copy the already not very clean drive
code file.
11) Write down the amount of BASIC and CODE parts
program.
12) In some monitor
at TR0, SEC0 offset by # 0D
burghers number, which we last
just remember.
13) Click RESET.
14) Copy BASIC-file from disk.
15) Fuh, work is done.
P.S. A long way, but what can you do ...
Using on-screen file ArtStd.
Using images ArtStudio too obvious
Hb is simple:
1) Run TASM
2) write:
ORG 25000
LD HL, adres_kartinki
LD DE, 16384
LD bc, 6912
LDIR
RET
3) Not forgetting, of course, go into BASIC
and typing RAND USR 15619: REM: LOAD "scr
n "CODE adres_kartinki
Solving certain problems.
A quote from a letter by Sergei Parfenov:
"And I did not get the compatibility,
For example, running a string created in assembler, with
melody, created in kakomlibo muses. editor. I have ever played
music, or go running line. "
About this problem I have
only one consideration (this problem is
the same once I am concerned): almost all
Players Mouzon change the case IX. A
you are in the program may register IX
used under the address of the current output symbol. So try
this:
...
main PUSH IX
CALL muzon
POP IX
CALL scroll
LD A, # 7F
IN A, (254)
RRCA
JR C, main
...
Unfortunately, I have never used
Editors Sprite Editor and Sprite Land.
I prefer only Art Studio. Even
to edit sprites it is not worse
mentioned above.
So read the next chapter.
Max. the rate of withdrawal of sprites
First you need to specify the format of the sprite.
Suppose, for example, Sprite in our X * Y
familiarity. Then write to BASIC'e prog
Rummy converting conventional Art-Studio-file 6912 bytes in the
sprite.
10 RAND USR 15619: REM: LOAD "scrn" CODE
16384
20 LET ADR = 50000
30 FOR J = 0 TO Y-1
40 FOR I = 0 TO X-1
50 FOR K = 0 TO 7
60 POKE ADR, PEEK
(16384 + I + J * 32 + K * 256)
70 LET ADR = ADR +1
80 NEXT K: NEXT I: NEXT J
90 PRINT "SAVE TO FILE XXX CODE",
ADR, "," ADR-50000
After running the program should be written
write file with the addresses of 50000 and a length
ADR-50000.
Now in TASM'e:
Downloading TASM, go to BASIC and load a sprite, for example,
under the address 50000.
ORG 25000
LD HL, 50000
LD A, y
L2 PUSH DE
EX AF, AF '
LD C, x
L1 PUSH HL
PUSH DE
LD B, 8
LP LD A, (HL)
LD (DE), A
INC HL
INC D
DJNZ LP
POP DE
POP HL
INC E
DEC C
JR NZ, L1
POP DE
LD A, E
ADD A, 32
LD E, A
EX AF, AF '
DEC A
JR NZ, L2
Program skorochena to the limit, to
You can easily understand how it works. Its shortcomings: the
sprite will be displayed correctly when it crosses the 1 / 3
part of the screen.
Input parameters: DE must register
indicate the starting point of a sprite.
And now the maximum speed.
For the case of withdrawal of a sprite of a variable
address of the sprite in a variable area of the screen the
following considerations:
1. If the width of the sprite is a multiple of 2 pixels (16
points), the fastest way O sprite following (excerpt):
Conclusion podsprayta 16 * 8 points
Repeat from the beginning of 4 times
HL = adres_sprayta
HL = адрес_вывода_спрайта_в_экр_обл Tee
LD A, (HL)
LD (DE), A
INC HL
INC E
LD A, (HL)
LD (DE), A
INC HL
INC D
LD A, (HL)
LD (DE), A
INC HL
DEC E
LD A, (HL)
LD (DE), A
INC D
; End
2. Note: Try to figure out
Why is used in the example command
no INC DE, and INC E.
3. If you want to make a conclusion sprite
to within 1 pixel, rather than to 8, then
without a buffer you can not do: the point is
that in all demos and almost all games
buffer is used for sprites, which is equal
8 (or usually more) dimensions
sprite without a buffer.
In the buffer is 8 sprites shifted by 0,1,2,3 .. 7 pixels.
As quickly as possible output points.
This problem has interested me for a long time.
I spent a lot of time to resolve it. However, to prove to you
that the next the procedure is perfectly fast, I,
Unfortunately, I can not, because a bummer.
Thus,
IDEAL FAST METHOD FOR THE POINT OF WITHDRAWAL
;!
LD H, TBL8880
LD D, (HL); senior video address
INC H
LD A, (HL); junior video address
INC H
LD L, C
ADD A, (HL); X / 8
INC H
LD E, A
LD A, (DE)
OR (HL)
LD (DE), A
;!
Only 69 cycles!
Before entering into this procedure to load the register L
Y-coordinate, and in Register C X-coordinate.
In this TBL8880 - is the most significant byte
address labels (for example, if the table
located at 25600, then TBL8880 =
= 25600/256 = 100), which is necessary to build
immediately after the start of the program, ie,
milli-dekranching. Here is its text:
LD DE, 256 * TBL8880
XOR A
lp PUSH AF
LD C, 0
CALL 8880
EX DE, HL
LD (HL), D
INC H
LD (HL), E
DEC H
INC L
EX DE, HL
POP AF
INC A
CP 192
JR NZ, lp
LD DE, 256 * TBL8880 +512
XOR A
l3 LD B, 8
l2 LD (DE), a
INC DE
DJNZ l2
INC A
CP 1932
JR NZ, l3
RET
Fastest stack up
Suppose, for example, we want to copy 16 bytes from one
region to another. Then the fastest way is (in my opinion, the
ideal, but I do not sure) to use the stack:
LD (TMP), SP
LD SP, FROM
POP HL
POP DE
POP BC
POP AF
EXX
EX AF, AF '
POP HL
POP DE
POP BC
POP AF
LD SP, TO +16
PUSH AF
PUSH BC
PUSH DE
PUSH HL
EX AF, AF '
EXX
PUSH AF
PUSH BC
PUSH DE
PUSH HL
LD SP, (TMP)
Here we use the register SP, so before you run the program
you want to disable call interrupt (DI), and before going to
the BASIC do not forget this:
LD HL, 10072
EXX
EI
All for today, I wait for new issues and
I hope they will be of interest to consider a wide range of
readers.
P.S. The programs may be some
inaccuracies, to put it simply, perhaps
that run them, they will be wrong
work. And why? Yes, because
rewrite it from. ASM file in lyricist
not very much fun. I believe that in
examples are given here, you must
penetrate, rather than typing them blindly on your computer. In
general, while, guys, see you again!
